Optimal. Leaf size=178 \[ -\frac{a d^2 \cosh \left (c-\frac{a d}{b}\right ) \text{Chi}\left (x d+\frac{a d}{b}\right )}{2 b^4}+\frac{d \sinh \left (c-\frac{a d}{b}\right ) \text{Chi}\left (x d+\frac{a d}{b}\right )}{b^3}-\frac{a d^2 \sinh \left (c-\frac{a d}{b}\right ) \text{Shi}\left (x d+\frac{a d}{b}\right )}{2 b^4}+\frac{d \cosh \left (c-\frac{a d}{b}\right ) \text{Shi}\left (x d+\frac{a d}{b}\right )}{b^3}+\frac{a d \sinh (c+d x)}{2 b^3 (a+b x)}-\frac{\cosh (c+d x)}{b^2 (a+b x)}+\frac{a \cosh (c+d x)}{2 b^2 (a+b x)^2} \]
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Rubi [A] time = 0.369989, antiderivative size = 178, normalized size of antiderivative = 1., number of steps used = 11, number of rules used = 5, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.333, Rules used = {6742, 3297, 3303, 3298, 3301} \[ -\frac{a d^2 \cosh \left (c-\frac{a d}{b}\right ) \text{Chi}\left (x d+\frac{a d}{b}\right )}{2 b^4}+\frac{d \sinh \left (c-\frac{a d}{b}\right ) \text{Chi}\left (x d+\frac{a d}{b}\right )}{b^3}-\frac{a d^2 \sinh \left (c-\frac{a d}{b}\right ) \text{Shi}\left (x d+\frac{a d}{b}\right )}{2 b^4}+\frac{d \cosh \left (c-\frac{a d}{b}\right ) \text{Shi}\left (x d+\frac{a d}{b}\right )}{b^3}+\frac{a d \sinh (c+d x)}{2 b^3 (a+b x)}-\frac{\cosh (c+d x)}{b^2 (a+b x)}+\frac{a \cosh (c+d x)}{2 b^2 (a+b x)^2} \]
Antiderivative was successfully verified.
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Rule 6742
Rule 3297
Rule 3303
Rule 3298
Rule 3301
Rubi steps
\begin{align*} \int \frac{x \cosh (c+d x)}{(a+b x)^3} \, dx &=\int \left (-\frac{a \cosh (c+d x)}{b (a+b x)^3}+\frac{\cosh (c+d x)}{b (a+b x)^2}\right ) \, dx\\ &=\frac{\int \frac{\cosh (c+d x)}{(a+b x)^2} \, dx}{b}-\frac{a \int \frac{\cosh (c+d x)}{(a+b x)^3} \, dx}{b}\\ &=\frac{a \cosh (c+d x)}{2 b^2 (a+b x)^2}-\frac{\cosh (c+d x)}{b^2 (a+b x)}+\frac{d \int \frac{\sinh (c+d x)}{a+b x} \, dx}{b^2}-\frac{(a d) \int \frac{\sinh (c+d x)}{(a+b x)^2} \, dx}{2 b^2}\\ &=\frac{a \cosh (c+d x)}{2 b^2 (a+b x)^2}-\frac{\cosh (c+d x)}{b^2 (a+b x)}+\frac{a d \sinh (c+d x)}{2 b^3 (a+b x)}-\frac{\left (a d^2\right ) \int \frac{\cosh (c+d x)}{a+b x} \, dx}{2 b^3}+\frac{\left (d \cosh \left (c-\frac{a d}{b}\right )\right ) \int \frac{\sinh \left (\frac{a d}{b}+d x\right )}{a+b x} \, dx}{b^2}+\frac{\left (d \sinh \left (c-\frac{a d}{b}\right )\right ) \int \frac{\cosh \left (\frac{a d}{b}+d x\right )}{a+b x} \, dx}{b^2}\\ &=\frac{a \cosh (c+d x)}{2 b^2 (a+b x)^2}-\frac{\cosh (c+d x)}{b^2 (a+b x)}+\frac{d \text{Chi}\left (\frac{a d}{b}+d x\right ) \sinh \left (c-\frac{a d}{b}\right )}{b^3}+\frac{a d \sinh (c+d x)}{2 b^3 (a+b x)}+\frac{d \cosh \left (c-\frac{a d}{b}\right ) \text{Shi}\left (\frac{a d}{b}+d x\right )}{b^3}-\frac{\left (a d^2 \cosh \left (c-\frac{a d}{b}\right )\right ) \int \frac{\cosh \left (\frac{a d}{b}+d x\right )}{a+b x} \, dx}{2 b^3}-\frac{\left (a d^2 \sinh \left (c-\frac{a d}{b}\right )\right ) \int \frac{\sinh \left (\frac{a d}{b}+d x\right )}{a+b x} \, dx}{2 b^3}\\ &=\frac{a \cosh (c+d x)}{2 b^2 (a+b x)^2}-\frac{\cosh (c+d x)}{b^2 (a+b x)}-\frac{a d^2 \cosh \left (c-\frac{a d}{b}\right ) \text{Chi}\left (\frac{a d}{b}+d x\right )}{2 b^4}+\frac{d \text{Chi}\left (\frac{a d}{b}+d x\right ) \sinh \left (c-\frac{a d}{b}\right )}{b^3}+\frac{a d \sinh (c+d x)}{2 b^3 (a+b x)}+\frac{d \cosh \left (c-\frac{a d}{b}\right ) \text{Shi}\left (\frac{a d}{b}+d x\right )}{b^3}-\frac{a d^2 \sinh \left (c-\frac{a d}{b}\right ) \text{Shi}\left (\frac{a d}{b}+d x\right )}{2 b^4}\\ \end{align*}
Mathematica [A] time = 0.578165, size = 158, normalized size = 0.89 \[ -\frac{d (a+b x)^2 \left (\text{Chi}\left (d \left (\frac{a}{b}+x\right )\right ) \left (a d \cosh \left (c-\frac{a d}{b}\right )-2 b \sinh \left (c-\frac{a d}{b}\right )\right )+\text{Shi}\left (d \left (\frac{a}{b}+x\right )\right ) \left (a d \sinh \left (c-\frac{a d}{b}\right )-2 b \cosh \left (c-\frac{a d}{b}\right )\right )\right )+b \cosh (d x) (b \cosh (c) (a+2 b x)-a d \sinh (c) (a+b x))-b \sinh (d x) (a d \cosh (c) (a+b x)-b \sinh (c) (a+2 b x))}{2 b^4 (a+b x)^2} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.036, size = 435, normalized size = 2.4 \begin{align*} -{\frac{{d}^{3}{{\rm e}^{-dx-c}}ax}{4\,{b}^{2} \left ({b}^{2}{d}^{2}{x}^{2}+2\,ab{d}^{2}x+{a}^{2}{d}^{2} \right ) }}-{\frac{{d}^{3}{{\rm e}^{-dx-c}}{a}^{2}}{4\,{b}^{3} \left ({b}^{2}{d}^{2}{x}^{2}+2\,ab{d}^{2}x+{a}^{2}{d}^{2} \right ) }}-{\frac{{d}^{2}{{\rm e}^{-dx-c}}x}{2\,b \left ({b}^{2}{d}^{2}{x}^{2}+2\,ab{d}^{2}x+{a}^{2}{d}^{2} \right ) }}-{\frac{{d}^{2}{{\rm e}^{-dx-c}}a}{4\,{b}^{2} \left ({b}^{2}{d}^{2}{x}^{2}+2\,ab{d}^{2}x+{a}^{2}{d}^{2} \right ) }}+{\frac{a{d}^{2}}{4\,{b}^{4}}{{\rm e}^{{\frac{da-cb}{b}}}}{\it Ei} \left ( 1,dx+c+{\frac{da-cb}{b}} \right ) }+{\frac{d}{2\,{b}^{3}}{{\rm e}^{{\frac{da-cb}{b}}}}{\it Ei} \left ( 1,dx+c+{\frac{da-cb}{b}} \right ) }+{\frac{{d}^{2}{{\rm e}^{dx+c}}a}{4\,{b}^{4}} \left ({\frac{da}{b}}+dx \right ) ^{-2}}+{\frac{{d}^{2}{{\rm e}^{dx+c}}a}{4\,{b}^{4}} \left ({\frac{da}{b}}+dx \right ) ^{-1}}+{\frac{a{d}^{2}}{4\,{b}^{4}}{{\rm e}^{-{\frac{da-cb}{b}}}}{\it Ei} \left ( 1,-dx-c-{\frac{da-cb}{b}} \right ) }-{\frac{d{{\rm e}^{dx+c}}}{2\,{b}^{3}} \left ({\frac{da}{b}}+dx \right ) ^{-1}}-{\frac{d}{2\,{b}^{3}}{{\rm e}^{-{\frac{da-cb}{b}}}}{\it Ei} \left ( 1,-dx-c-{\frac{da-cb}{b}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} b \int \frac{x e^{\left (d x + c\right )}}{b^{4} d x^{4} + 4 \, a b^{3} d x^{3} + 6 \, a^{2} b^{2} d x^{2} + 4 \, a^{3} b d x + a^{4} d}\,{d x} - b \int \frac{x}{b^{4} d x^{4} e^{\left (d x + c\right )} + 4 \, a b^{3} d x^{3} e^{\left (d x + c\right )} + 6 \, a^{2} b^{2} d x^{2} e^{\left (d x + c\right )} + 4 \, a^{3} b d x e^{\left (d x + c\right )} + a^{4} d e^{\left (d x + c\right )}}\,{d x} + \frac{x e^{\left (d x + 2 \, c\right )} - x e^{\left (-d x\right )}}{2 \,{\left (b^{3} d x^{3} e^{c} + 3 \, a b^{2} d x^{2} e^{c} + 3 \, a^{2} b d x e^{c} + a^{3} d e^{c}\right )}} - \frac{a e^{\left (-c + \frac{a d}{b}\right )} E_{4}\left (\frac{{\left (b x + a\right )} d}{b}\right )}{2 \,{\left (b x + a\right )}^{3} b d} + \frac{a e^{\left (c - \frac{a d}{b}\right )} E_{4}\left (-\frac{{\left (b x + a\right )} d}{b}\right )}{2 \,{\left (b x + a\right )}^{3} b d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.23575, size = 770, normalized size = 4.33 \begin{align*} -\frac{2 \,{\left (2 \, b^{3} x + a b^{2}\right )} \cosh \left (d x + c\right ) +{\left ({\left (a^{3} d^{2} - 2 \, a^{2} b d +{\left (a b^{2} d^{2} - 2 \, b^{3} d\right )} x^{2} + 2 \,{\left (a^{2} b d^{2} - 2 \, a b^{2} d\right )} x\right )}{\rm Ei}\left (\frac{b d x + a d}{b}\right ) +{\left (a^{3} d^{2} + 2 \, a^{2} b d +{\left (a b^{2} d^{2} + 2 \, b^{3} d\right )} x^{2} + 2 \,{\left (a^{2} b d^{2} + 2 \, a b^{2} d\right )} x\right )}{\rm Ei}\left (-\frac{b d x + a d}{b}\right )\right )} \cosh \left (-\frac{b c - a d}{b}\right ) - 2 \,{\left (a b^{2} d x + a^{2} b d\right )} \sinh \left (d x + c\right ) -{\left ({\left (a^{3} d^{2} - 2 \, a^{2} b d +{\left (a b^{2} d^{2} - 2 \, b^{3} d\right )} x^{2} + 2 \,{\left (a^{2} b d^{2} - 2 \, a b^{2} d\right )} x\right )}{\rm Ei}\left (\frac{b d x + a d}{b}\right ) -{\left (a^{3} d^{2} + 2 \, a^{2} b d +{\left (a b^{2} d^{2} + 2 \, b^{3} d\right )} x^{2} + 2 \,{\left (a^{2} b d^{2} + 2 \, a b^{2} d\right )} x\right )}{\rm Ei}\left (-\frac{b d x + a d}{b}\right )\right )} \sinh \left (-\frac{b c - a d}{b}\right )}{4 \,{\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.23384, size = 714, normalized size = 4.01 \begin{align*} -\frac{a b^{2} d^{2} x^{2}{\rm Ei}\left (\frac{b d x + a d}{b}\right ) e^{\left (c - \frac{a d}{b}\right )} + a b^{2} d^{2} x^{2}{\rm Ei}\left (-\frac{b d x + a d}{b}\right ) e^{\left (-c + \frac{a d}{b}\right )} + 2 \, a^{2} b d^{2} x{\rm Ei}\left (\frac{b d x + a d}{b}\right ) e^{\left (c - \frac{a d}{b}\right )} - 2 \, b^{3} d x^{2}{\rm Ei}\left (\frac{b d x + a d}{b}\right ) e^{\left (c - \frac{a d}{b}\right )} + 2 \, a^{2} b d^{2} x{\rm Ei}\left (-\frac{b d x + a d}{b}\right ) e^{\left (-c + \frac{a d}{b}\right )} + 2 \, b^{3} d x^{2}{\rm Ei}\left (-\frac{b d x + a d}{b}\right ) e^{\left (-c + \frac{a d}{b}\right )} + a^{3} d^{2}{\rm Ei}\left (\frac{b d x + a d}{b}\right ) e^{\left (c - \frac{a d}{b}\right )} - 4 \, a b^{2} d x{\rm Ei}\left (\frac{b d x + a d}{b}\right ) e^{\left (c - \frac{a d}{b}\right )} + a^{3} d^{2}{\rm Ei}\left (-\frac{b d x + a d}{b}\right ) e^{\left (-c + \frac{a d}{b}\right )} + 4 \, a b^{2} d x{\rm Ei}\left (-\frac{b d x + a d}{b}\right ) e^{\left (-c + \frac{a d}{b}\right )} - a b^{2} d x e^{\left (d x + c\right )} + a b^{2} d x e^{\left (-d x - c\right )} - 2 \, a^{2} b d{\rm Ei}\left (\frac{b d x + a d}{b}\right ) e^{\left (c - \frac{a d}{b}\right )} + 2 \, a^{2} b d{\rm Ei}\left (-\frac{b d x + a d}{b}\right ) e^{\left (-c + \frac{a d}{b}\right )} - a^{2} b d e^{\left (d x + c\right )} + 2 \, b^{3} x e^{\left (d x + c\right )} + a^{2} b d e^{\left (-d x - c\right )} + 2 \, b^{3} x e^{\left (-d x - c\right )} + a b^{2} e^{\left (d x + c\right )} + a b^{2} e^{\left (-d x - c\right )}}{4 \,{\left (b^{6} x^{2} + 2 \, a b^{5} x + a^{2} b^{4}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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